Math.IEEERemainder メソッド

.NET Framework クラス ライブラリ リファレンス

Math.IEEERemainder メソッド

指定した数を別の指定数で除算した結果の剰余を返します。

名前空間: System
アセンブリ: mscorlib (mscorlib.dll 内)
構文

Visual Basic (宣言)

Public Shared Function IEEERemainder
 ( _
    x As Double, _
    y As Double _
) As Double

Visual Basic (使用法)

Dim x As Double
Dim y As Double
Dim returnValue As Double

returnValue = Math.IEEERemainder(x, y)

C#

public static double IEEERemainder (
    double x,
    double y
)

C++

public:
static double IEEERemainder (
    double x, 
    double y
)

J#

public static double IEEERemainder (
    double x, 
    double y
)

JScript

public static function IEEERemainder
 (
    x : double, 
    y : double
) : double

パラメータ

x

被除数。

y

除数。

戻り値
x - ( y Q) に等しい数値。Q は x / y の商を丸めた近似整数を示します。x / y が 2 つの整数の中間に位置する場合は、偶数の整数が返されます。 x - ( y Q) が 0 のとき、x が正である場合は値 +0 が、x が負である場合は値 -0 が返されます。 y = 0 の場合は、NaN (Not-A-Number) が返されます。

解説

この演算は、ANSI/IEEE 規格 754-1985 のセクション 5.1 「IEEE Standard for Binary Floating-Point Arithmetic」(米国電気電子技術者協会 (IEEE: Institute of Electrical and Electronics Engineers, Inc)、1985) に定義されている剰余演算に準拠しています。

使用例

Visual Basic

' This example demonstrates Math.DivRem()
'                           Math.IEEERemainder()
Imports System

Class Sample
   Public Shared Sub Main()
      Dim int1 As Integer
 = Int32.MaxValue
      Dim int2 As Integer
 = Int32.MaxValue
      Dim intResult As Integer
      Dim long1 As Long
 = Int64.MaxValue
      Dim long2 As Long
 = Int64.MaxValue
      Dim longResult As Long
      Dim doubleResult As Double
      Dim divisor As Double
      Dim nl As [String] = Environment.NewLine
      '
      Console.WriteLine("{0}Calculate the quotient and remainder
 of two Int32 values:", nl)
      intResult = Math.DivRem(int1, 2, int2)
      Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.",
 int1, 2, intResult, int2)
      '
      Console.WriteLine("{0}Calculate the quotient and remainder
 of two Int64 values:", nl)
      longResult = Math.DivRem(long1, 4, long2)
      Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.",
 long1, 4, longResult, long2)
      '
      Dim str1 As [String] = "The
 IEEE remainder of {0:e}/{1:f} is {2:e}"
      divisor = 2.0
      Console.WriteLine("{0}Divide two double-precision floating-point
 values:", nl)
      doubleResult = Math.IEEERemainder([Double].MaxValue, divisor)
      Console.Write("1) ")
      Console.WriteLine(str1, [Double].MaxValue, divisor, doubleResult)
      
      divisor = 3.0
      doubleResult = Math.IEEERemainder([Double].MaxValue, divisor)
      Console.Write("2) ")
      Console.WriteLine(str1, [Double].MaxValue, divisor, doubleResult)
      Console.WriteLine("Note that two positive numbers can yield
 a negative remainder.")
   End Sub 'Main
End Class 'Sample
'
'This example produces the following results:
'
'Calculate the quotient and remainder of two Int32 values:
'2147483647/2 = 1073741823, with a remainder of 1.
'
'Calculate the quotient and remainder of two Int64 values:
'9223372036854775807/4 = 2305843009213693951, with a remainder of 3.
'
'Divide two double-precision floating-point values:
'1) The IEEE remainder of 1.797693e+308/2.00 is 0.000000e+000
'2) The IEEE remainder of 1.797693e+308/3.00 is -1.000000e+000
'Note that two positive numbers can yield a negative remainder.
'

C#

// This example demonstrates Math.DivRem()
//                           Math.IEEERemainder()
using System;

class Sample 
{
    public static void Main()
 
    {
    int int1 = Int32.MaxValue;
    int int2 = Int32.MaxValue;
    int intResult;
    long long1 = Int64.MaxValue;
    long long2 = Int64.MaxValue;
    long longResult;
    double doubleResult;
    double divisor;
    String nl = Environment.NewLine;
//
    Console.WriteLine("{0}Calculate the quotient and remainder of two Int32
 values:", nl);
    intResult = Math.DivRem(int1, 2, out int2);
    Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.", int1,
 2, intResult, int2);
//
    Console.WriteLine("{0}Calculate the quotient and remainder of two Int64
 values:", nl);
    longResult = Math.DivRem(long1, 4, out long2);
    Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.", long1,
 4, longResult, long2);
//
    String str1 = "The IEEE remainder of {0:e}/{1:f} is {2:e}";
    divisor = 2.0;
    Console.WriteLine("{0}Divide two double-precision floating-point values:",
 nl);
    doubleResult = Math.IEEERemainder(Double.MaxValue, divisor);
    Console.Write("1) ");
    Console.WriteLine(str1, Double.MaxValue, divisor, doubleResult);

    divisor = 3.0;
    doubleResult = Math.IEEERemainder(Double.MaxValue, divisor);
    Console.Write("2) ");
    Console.WriteLine(str1, Double.MaxValue, divisor, doubleResult);
    Console.WriteLine("Note that two positive numbers can yield a negative remainder.");
    }
}
/*
This example produces the following results:

Calculate the quotient and remainder of two Int32 values:
2147483647/2 = 1073741823, with a remainder of 1.

Calculate the quotient and remainder of two Int64 values:
9223372036854775807/4 = 2305843009213693951, with a remainder of 3.

Divide two double-precision floating-point values:
1) The IEEE remainder of 1.797693e+308/2.00 is 0.000000e+000
2) The IEEE remainder of 1.797693e+308/3.00 is -1.000000e+000
Note that two positive numbers can yield a negative remainder.

*/

C++

// This example demonstrates Math.DivRem()
//                           Math.IEEERemainder()
using namespace System;
int main()
{
   int int1 = Int32::MaxValue;
   int int2 = Int32::MaxValue;
   int intResult;
   Int64 long1 = Int64::MaxValue;
   Int64 long2 = Int64::MaxValue;
   Int64 longResult;
   double doubleResult;
   double divisor;
   String^ nl = Environment::NewLine;
   
   //
   Console::WriteLine( "{0}Calculate the quotient and remainder of two Int32
 values:", nl );
   intResult = Math::DivRem( int1, 2, int2 );
   Console::WriteLine( "{0}/{1} = {2}, with a remainder of {3}.", int1,
 2, intResult, int2 );
   
   //
   Console::WriteLine( "{0}Calculate the quotient and remainder of two Int64
 values:", nl );
   longResult = Math::DivRem( long1, 4, long2 );
   Console::WriteLine( "{0}/{1} = {2}, with a remainder of {3}.", long1,
 4, longResult, long2 );
   
   //
   String^ str1 = "The IEEE remainder of {0:e}/{1:f} is {2:e}";
   divisor = 2.0;
   Console::WriteLine( "{0}Divide two double-precision floating-point values:",
 nl );
   doubleResult = Math::IEEERemainder( Double::MaxValue, divisor );
   Console::Write( "1) " );
   Console::WriteLine( str1, Double::MaxValue, divisor, doubleResult );
   divisor = 3.0;
   doubleResult = Math::IEEERemainder( Double::MaxValue, divisor );
   Console::Write( "2) " );
   Console::WriteLine( str1, Double::MaxValue, divisor, doubleResult );
   Console::WriteLine( "Note that two positive numbers can yield a negative
 remainder." );
}

/*
This example produces the following results:

Calculate the quotient and remainder of two Int32 values:
2147483647/2 = 1073741823, with a remainder of 1.

Calculate the quotient and remainder of two Int64 values:
9223372036854775807/4 = 2305843009213693951, with a remainder of 3.

Divide two double-precision floating-point values:
1) The IEEE remainder of 1.797693e+308/2.00 is 0.000000e+000
2) The IEEE remainder of 1.797693e+308/3.00 is -1.000000e+000
Note that two positive numbers can yield a negative remainder.
*/

J#

// This example demonstrates Math.DivRem()
// Math.IEEERemainder()
import System.*;

class Sample
{
    public static void main(String[]
 args)
    {
        int int1 = Int32.MaxValue;
        int int2 = Int32.MaxValue;
        int intResult;
        long long1 = Int64.MaxValue;
        long long2 = Int64.MaxValue;
        long longResult;
        double doubleResult;
        double divisor;
        String nl = Environment.get_NewLine();
        //
        Console.WriteLine("{0}Calculate the quotient and " 
            + "remainder of two Int32 values:", nl);
        intResult = System.Math.DivRem(int1, 2, int2);
        Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.", 
            new Object[] { (Int32)int1, (Int32)2,
            (Int32)intResult, (Int32)int2 });
        //
        Console.WriteLine("{0}Calculate the quotient and remainder" 
            + " of two Int64 values:", nl);
        longResult = System.Math.DivRem(long1, 4, long2);
        Console.WriteLine("{0}/{1} = {2}, with a remainder of {3}.", 
            new Object[] { (Int64)long1, (Int32)4, 
            (Int64)longResult, (Int64)long2    });
        //
        String str1 = "The IEEE remainder of {0:e}/{1:f} is {2:e}";
        divisor = 2.0;
        Console.WriteLine("{0}Divide two double-precision" 
            + " floating-point values:", nl);
        doubleResult = System.Math.IEEERemainder(System.Double.MaxValue, divisor);
        Console.Write("1) ");
        Console.WriteLine(str1, 
            ((System.Double)System.Double.MaxValue).ToString("e"),
            ((System.Double)divisor).ToString("f"),
            ((System.Double)doubleResult).ToString("e"));

        divisor = 3.0;
        doubleResult = System.Math.IEEERemainder(System.Double.MaxValue, divisor);
        Console.Write("2) ");
        Console.WriteLine(str1,
            ((System.Double)System.Double.MaxValue).ToString("e"), 
            ((System.Double)divisor).ToString("f"),
            ((System.Double)doubleResult).ToString("e"));
        Console.WriteLine("Note that two positive numbers can" 
            + " yield a negative remainder.");
    } //main
} //Sample

/*
This example produces the following results:

Calculate the quotient and remainder of two Int32 values:
2147483647/2 = 1073741823, with a remainder of 1.

Calculate the quotient and remainder of two Int64 values:
9223372036854775807/4 = 2305843009213693951, with a remainder of 3.

Divide two double-precision floating-point values:
1) The IEEE remainder of 1.797693e+308/2.00 is 0.000000e+000
2) The IEEE remainder of 1.797693e+308/3.00 is -1.000000e+000
Note that two positive numbers can yield a negative remainder.
*/

プラットフォーム

Windows 98, Windows 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

開発プラットフォームの中には、.NET Framework によってサポートされていないバージョンがあります。サポートされているバージョンについては、「システム要件」を参照してください。

バージョン情報

.NET Framework
サポート対象 : 2.0、1.1、1.0
.NET Compact Framework
サポート対象 : 2.0、1.0

参照

関連項目
Math クラス
Math メンバ
System 名前空間