XmlChoiceIdentifierAttribute コンストラクタとは何？わかりやすく解説 Weblio辞書

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.NET Framework クラスライブラリリファレンス

索引トップ用語の索引ランキング

XmlChoiceIdentifierAttribute コンストラクタ (String)

XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。

名前空間: System.Xml.Serialization
アセンブリ: System.Xml (system.xml.dll 内)
構文

Visual Basic (宣言)

Public Sub New ( _
    name As String _
)

Visual Basic (使用法)

Dim name As String

Dim instance As New XmlChoiceIdentifierAttribute(name)

public XmlChoiceIdentifierAttribute (
    string name
)

C++

public:
XmlChoiceIdentifierAttribute (
    String^ name
)

public XmlChoiceIdentifierAttribute (
    String name
)

JScript

public function XmlChoiceIdentifierAttribute
 (
    name : String
)

パラメータ

name: メンバを検出するために使用される列挙体を返すメンバ名。

プラットフォーム

Windows 98, Windows 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

開発プラットフォームの中には、.NET Framework によってサポートされていないバージョンがあります。サポートされているバージョンについては、「システム要件」を参照してください。

バージョン情報

.NET Framework
サポート対象 : 2.0、1.1、1.0
.NET Compact Framework
サポート対象 : 2.0、1.0

参照

関連項目
XmlChoiceIdentifierAttribute クラス
XmlChoiceIdentifierAttribute メンバ
System.Xml.Serialization 名前空間

XmlChoiceIdentifierAttribute コンストラクタ

XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。
オーバーロードの一覧

名前	説明
XmlChoiceIdentifierAttribute ()	XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。 .NET Compact Framework によってサポートされています。
XmlChoiceIdentifierAttribute (String)	XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。 .NET Compact Framework によってサポートされています。

参照

XmlChoiceIdentifierAttribute コンストラクタ ()

XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。

名前空間: System.Xml.Serialization
アセンブリ: System.Xml (system.xml.dll 内)
構文

Visual Basic (宣言)

Public Sub New

Visual Basic (使用法)

Dim instance As New XmlChoiceIdentifierAttribute

public XmlChoiceIdentifierAttribute ()

C++

public:
XmlChoiceIdentifierAttribute ()

public XmlChoiceIdentifierAttribute ()

JScript

public function XmlChoiceIdentifierAttribute
 ()

使用例

MyChoice と ManyChoices という 2 つのフィールドを含んでいる Choices という名前のクラスをシリアル化する例を次に示します。各フィールドに XmlChoiceIdentifierAttribute が適用されており、これらのフィールドは、MemberName プロパティを使用して、それぞれのメンバの値を検出するための列挙体を取得または設定する別のクラスメンバを指定しています。MyChoice フィールドには、対応する列挙体メンバが EnumType フィールド内に存在している単一の値を設定できます。ManyChoices フィールドは、オブジェクトの配列を返します。ChoiceArray フィールドは、列挙値の配列を返します。ManyChoices フィールドの各配列メンバに対応するメンバが、ChoiceArray フィールドによって返される配列の中に見つかります。

Visual Basic

Imports System
Imports System.Xml
Imports System.Xml.Serialization
Imports System.IO

Public Class Choices
   ' The MyChoice field can be set to any one of 
   ' the types below. 
   <XmlChoiceIdentifier("EnumType"), _
   XmlElement("Word", GetType(String)),
 _
   XmlElement("Number", GetType(Integer)),
 _
   XmlElement("DecimalNumber", GetType(double))>
 _
   Public MyChoice As Object
 

   ' Don't serialize this field. The EnumType field
   ' contains the enumeration value that corresponds
   ' to the MyChoice field value.
   <XmlIgnore> _
   Public EnumType As ItemChoiceType 

   'The ManyChoices field can contain an array
   ' of choices. Each choice must be matched to
   ' an array item in the ChoiceArray field.
   <XmlChoiceIdentifier("ChoiceArray"), _
   XmlElement("Item", GetType(string)),
 _
   XmlElement("Amount", GetType(Integer)),
 _
   XmlElement("Temp", GetType(double))>
 _
   Public ManyChoices() As Object

   ' TheChoiceArray field contains the enumeration
   ' values, one for each item in the ManyChoices array.
   <XmlIgnore> _
   Public ChoiceArray() As MoreChoices
End Class

<XmlType(IncludeInSchema:=false)> _
Public Enum ItemChoiceType
   None
   Word 
   Number
   DecimalNumber
End Enum

<XmlType(IncludeInSchema:=false)> _
Public Enum MoreChoices
   None
   Item
   Amount
   Temp
End Enum

Public Class Test
   Shared Sub Main()
      Dim t  As Test = New
 Test()
      t.SerializeObject("Choices.xml")
      t.DeserializeObject("Choices.xml")
   End Sub

   private Sub SerializeObject(filename As
 string)
      Dim mySerializer As XmlSerializer = _
      New XmlSerializer(GetType(Choices))
      Dim writer As TextWriter = New
 StreamWriter(filename)
      Dim myChoices As Choices = New
 Choices()

      ' Set the MyChoice field to a string. Set the
      ' EnumType to Word.
      myChoices.MyChoice= "Book"
      myChoices.EnumType = ItemChoiceType.Word

      ' Populate an object array with three items, one
      ' of each enumeration type. Set the array to the 
      ' ManyChoices field.
      Dim strChoices () As Object
 = New object(){"Food",
  5, 98.6}
      myChoices.ManyChoices=strChoices

      ' For each item in the ManyChoices array, add an
      ' enumeration value.
      Dim itmChoices () As MoreChoices = New
 MoreChoices() _
      {MoreChoices.Item, _
      MoreChoices.Amount, _
      MoreChoices.Temp}
      myChoices.ChoiceArray=itmChoices
      
      mySerializer.Serialize(writer, myChoices)
      writer.Close()
   End Sub

   private Sub DeserializeObject(filename As
 string)
      Dim ser As XmlSerializer = New
 XmlSerializer(GetType(Choices))
      

      ' A FileStream is needed to read the XML document.
      Dim fs As FileStream = New
 FileStream(filename, FileMode.Open)
      
      Dim myChoices As Choices = CType(ser.Deserialize(fs),
 Choices)

      fs.Close()

      ' Disambiguate the MyChoice value Imports the enumeration.
      if myChoices.EnumType = ItemChoiceType.Word Then
             Console.WriteLine("Word: " & _
             myChoices.MyChoice.ToString())
          
      else if myChoices.EnumType = ItemChoiceType.Number
 Then 
             Console.WriteLine("Number: " & _
                 myChoices.MyChoice.ToString())
          
      else if myChoices.EnumType = ItemChoiceType.DecimalNumber
 Then
         Console.WriteLine("DecimalNumber: " &
 _
                 myChoices.MyChoice.ToString())
          End If

      ' Disambiguate the ManyChoices values Imports the enumerations.
      Dim i As Integer
      for i = 0 to myChoices.ManyChoices.Length
 -1
      if myChoices.ChoiceArray(i) = MoreChoices.Item Then
          Console.WriteLine("Item: " +  _
          myChoices.ManyChoices(i).ToString())
      else if myChoices.ChoiceArray(i) = MoreChoices.Amount
 Then
          Console.WriteLine("Amount: " + _
          myChoices.ManyChoices(i).ToString())
      else if (myChoices.ChoiceArray(i) = MoreChoices.Temp)
          Console.WriteLine("Temp: " + _
          myChoices.ManyChoices(i).ToString())
          End If
          Next i
      
   End Sub
End Class

using System;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

public class Choices{
   // The MyChoice field can be set to any one of 
   // the types below. 
   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word", typeof(string))]
   [XmlElement("Number", typeof(int))]
   [XmlElement("DecimalNumber", typeof(double))]
   public object MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.
   [XmlIgnore]
   public ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.
   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item", typeof(string))]
   [XmlElement("Amount", typeof(int))]
   [XmlElement("Temp", typeof(double))]
   public object[] ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.
   [XmlIgnore]
   public MoreChoices[] ChoiceArray;
}

[XmlType(IncludeInSchema=false)]
public enum ItemChoiceType{
   None,
   Word, 
   Number,
   DecimalNumber
}

public enum MoreChoices{
   None,
   Item,
   Amount,
   Temp
}

public class Test{
   static void Main(){
      Test t = new Test();
      t.SerializeObject("Choices.xml");
      t.DeserializeObject("Choices.xml");
   }

   private void SerializeObject(string
 filename){
      XmlSerializer mySerializer = 
      new XmlSerializer(typeof(Choices));
      TextWriter writer = new StreamWriter(filename);
      Choices myChoices = new Choices();

      // Set the MyChoice field to a string. Set the
      // EnumType to Word.
      myChoices.MyChoice= "Book";
      myChoices.EnumType = ItemChoiceType.Word;

      // Populate an object array with three items, one
      // of each enumeration type. Set the array to the 
      // ManyChoices field.
      object[] strChoices = new object[]{"Food",  5,
 98.6};
      myChoices.ManyChoices=strChoices;

      // For each item in the ManyChoices array, add an
      // enumeration value.
      MoreChoices[] itmChoices = new MoreChoices[]
      {MoreChoices.Item, 
      MoreChoices.Amount,
      MoreChoices.Temp};
      myChoices.ChoiceArray=itmChoices;
      
      mySerializer.Serialize(writer, myChoices);
      writer.Close();
   }

   private void DeserializeObject(string
 filename){
      XmlSerializer ser = new XmlSerializer(typeof(Choices));

      // A FileStream is needed to read the XML document.
      FileStream fs = new FileStream(filename, FileMode.Open);
      Choices myChoices = (Choices)
      ser.Deserialize(fs);
      fs.Close();

      // Disambiguate the MyChoice value using the enumeration.
      if(myChoices.EnumType == ItemChoiceType.Word){
             Console.WriteLine("Word: " +  
                 myChoices.MyChoice.ToString());
          }
      else if(myChoices.EnumType == ItemChoiceType.Number){
             Console.WriteLine("Number: " +
                 myChoices.MyChoice.ToString());
          }
      else if(myChoices.EnumType == ItemChoiceType.DecimalNumber){
             Console.WriteLine("DecimalNumber: " +
                 myChoices.MyChoice.ToString());
          }

      // Disambiguate the ManyChoices values using the enumerations.
      for(int i = 0; i<myChoices.ManyChoices.Length;
 i++){
      if(myChoices.ChoiceArray[i] == MoreChoices.Item)
          Console.WriteLine("Item: " + (string) myChoices.ManyChoices[i]);
      else if(myChoices.ChoiceArray[i] == MoreChoices.Amount)
          Console.WriteLine("Amount: " + myChoices.ManyChoices[i].ToString());
      if(myChoices.ChoiceArray[i] == MoreChoices.Temp)
          Console.WriteLine("Temp: " + (string) myChoices.ManyChoices[i].ToString());
          }
      
   }
}

C++

#using <System.dll>
#using <System.xml.dll>

using namespace System;
using namespace System::Xml;
using namespace System::Xml::Serialization;
using namespace System::IO;

[XmlType(IncludeInSchema=false)]

public enum class ItemChoiceType
{
   None, Word, Number, DecimalNumber
};

public enum class MoreChoices
{
   None, Item, Amount, Temp
};

public ref class Choices
{
public:

   // The MyChoice field can be set to any one of 
   // the types below. 

   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word",String::typeid)]
   [XmlElement("Number",Int32::typeid)]
   [XmlElement("DecimalNumber",Double::typeid)]
   Object^ MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.

   [XmlIgnore]
   ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.

   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item",String::typeid)]
   [XmlElement("Amount",Int32::typeid)]
   [XmlElement("Temp",Double::typeid)]
   array<Object^>^ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.

   [XmlIgnore]
   array<MoreChoices>^ChoiceArray;
};

void SerializeObject( String^ filename );
void DeserializeObject( String^ filename );
int main()
{
   SerializeObject( "Choices.xml" );
   DeserializeObject( "Choices.xml" );
}

void SerializeObject( String^ filename )
{
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Choices::typeid );
   TextWriter^ writer = gcnew StreamWriter( filename );
   Choices^ myChoices = gcnew Choices;

   // Set the MyChoice field to a string. Set the
   // EnumType to Word.
   myChoices->MyChoice = "Book";
   myChoices->EnumType = ItemChoiceType::Word;

   // Populate an object array with three items, one
   // of each enumeration type. Set the array to the 
   // ManyChoices field.
   array<Object^>^strChoices = {"Food",5,98.6};
   myChoices->ManyChoices = strChoices;

   // For each item in the ManyChoices array, add an
   // enumeration value.
   array<MoreChoices>^ itmChoices = {MoreChoices::Item,MoreChoices::Amount
,MoreChoices::Temp};
   myChoices->ChoiceArray = itmChoices;
   mySerializer->Serialize( writer, myChoices );
   writer->Close();
}

void DeserializeObject( String^ filename )
{
   XmlSerializer^ ser = gcnew XmlSerializer( Choices::typeid );

   // A FileStream is needed to read the XML document.
   FileStream^ fs = gcnew FileStream( filename,FileMode::Open );
   Choices^ myChoices = safe_cast<Choices^>(ser->Deserialize( fs ));
   fs->Close();

   // Disambiguate the MyChoice value using the enumeration.
   if ( myChoices->EnumType == ItemChoiceType::Word )
   {
      Console::WriteLine( "Word: {0}", myChoices->MyChoice->ToString()
 );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::Number )
   {
      Console::WriteLine( "Number: {0}", myChoices->MyChoice->ToString()
 );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::DecimalNumber
 )
   {
      Console::WriteLine( "DecimalNumber: {0}", myChoices->MyChoice->ToString()
 );
   }

   // Disambiguate the ManyChoices values using the enumerations.
   for ( int i = 0; i < myChoices->ManyChoices->Length;
 i++ )
   {
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Item
 )
            Console::WriteLine( "Item: {0}", myChoices->ManyChoices[
 i ] );
      else
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Amount
 )
            Console::WriteLine( "Amount: ", myChoices->ManyChoices[
 i ]->ToString() );
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Temp
 )
            Console::WriteLine( "Temp: {0}", myChoices->ManyChoices[
 i ]->ToString() );
   }
}

import System.*;
import System.Xml.*;
import System.Xml.Serialization.*;
import System.IO.*;
public class Choices
{
    // The myChoice field can be set to any one of 
    // the types below. 
    /** @attribute XmlElement("word", String.class)
     */
    /** @attribute XmlElement("Number", int.class)
     */
    /** @attribute XmlElement("DecimalNumber", double.class)
     */
    public Object myChoice;

    // Don't serialize this field. The EnumType field
    // contains the enumeration value that corresponds
    // to the myChoice field value.
    public int enumType;

    // The manyChoices field can contain an array
    // of choices. Each choice must be matched to
    // an array item in the choiceArray field.
    /** @attribute XmlElement("Item", String.class)
     */
    /** @attribute XmlElement("amount", int.class)
     */
    /** @attribute XmlElement("temp", double.class)
     */
    public Object manyChoices[];

    // ThechoiceArray field contains the enumeration
    // values, one for each item in the manyChoices array.
    public int choiceArray[];
} //Choices

/** @attribute XmlType(IncludeInSchema = false)
 */
public class ItemChoiceType
{
    public static final int
 none = 0;
    public static final int
 word = 1;
    public static final int
 number = 2;
    public static final int
 decimalNumber = 3;
} //ItemChoiceType

public class MoreChoices
{
    public static final int
 none = 0;
    public static final int
 item = 1;
    public static final int
 amount = 2;
    public static final int
 temp = 3;
} //MoreChoices

public class Test
{
    public static void main(String[]
 args)
    {
        Test t = new Test();
        t.SerializeObject("Choices.xml");
        t.DeserializeObject("Choices.xml");
    } //main

    private void SerializeObject(String fileName)
    {
        XmlSerializer mySerializer = new XmlSerializer(Choices.class.ToType());
        TextWriter writer = new StreamWriter(fileName);
        Choices myChoices = new Choices();
        // Set the myChoice field to a string. Set the
        // enumType to word.
        myChoices.myChoice = "Book";
        myChoices.enumType = ItemChoiceType.word;
        // Populate an object array with three items, one
        // of each enumeration type. Set the array to the 
        // manyChoices field.
        Object strChoices[] = new Object[] { "Food",
 (Int32)5,
            (System.Double)98.6 };
        myChoices.manyChoices = strChoices;
        // For each item in the manyChoices array, add an
        // enumeration value.
        int itmChoices[] = new int[]
 {
            MoreChoices.item, MoreChoices.amount, MoreChoices.temp
        };

        myChoices.choiceArray = new int[itmChoices.get_Length()];
        itmChoices.CopyTo(myChoices.choiceArray, 0);

        //myChoices.choiceArray = itmChoices;
        mySerializer.Serialize(writer, myChoices);
        writer.Close();
    } //SerializeObject

    private void DeserializeObject(String fileName)
    {
        XmlSerializer ser = new XmlSerializer(Choices.class.ToType());
        // A FileStream is needed to read the XML document.
        FileStream fs = new FileStream(fileName, FileMode.Open);
        Choices myChoices = (Choices)ser.Deserialize(fs);
        fs.Close();
        // Disambiguate the myChoice value using the enumeration.
        if (myChoices.enumType == ItemChoiceType.word) {
            Console.WriteLine("Word: " + myChoices.myChoice.ToString());
        }
        else {
            if (myChoices.enumType == ItemChoiceType.number) {
                Console.WriteLine("Number: " + myChoices.myChoice.ToString());
            }
            else {
                if (myChoices.enumType == ItemChoiceType.decimalNumber)
 {
                    Console.WriteLine("DecimalNumber: " +
                        myChoices.myChoice.ToString());
                }
            }
        }
        // Disambiguate the manyChoices values using the enumerations.
        for (int i = 0; i < myChoices.manyChoices.get_Length();
 i++) {
            if (System.Convert.ToInt32(myChoices.choiceArray.get_Item(i))
 ==
                MoreChoices.item) {
                Console.WriteLine("Item: " 
                    + (String)(myChoices.manyChoices.get_Item(i)));
            }
            else {
                if (System.Convert.ToInt32(myChoices.choiceArray.
                    get_Item(i)) == MoreChoices.amount) {
                    Console.WriteLine("Amount: " +
                        myChoices.manyChoices.get_Item(i).ToString());
                }
            }
            if (System.Convert.ToInt32(myChoices.choiceArray.
                get_Item(i)) == MoreChoices.temp) {
                Console.WriteLine("Temp: " + (String)(
                    myChoices.manyChoices.get_Item(i).ToString()));
            }
        }
    } //DeserializeObject 
} //Test

プラットフォーム

バージョン情報

.NET Framework
サポート対象 : 2.0、1.1、1.0
.NET Compact Framework
サポート対象 : 2.0、1.0

参照

関連項目
XmlChoiceIdentifierAttribute クラス
XmlChoiceIdentifierAttribute メンバ
System.Xml.Serialization 名前空間

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XmlChoiceIdentifierAttribute コンストラクタとは？わかりやすく解説

XmlChoiceIdentifierAttribute コンストラクタ (String)

XmlChoiceIdentifierAttribute コンストラクタ

関連項目

XmlChoiceIdentifierAttribute コンストラクタ ()

「XmlChoiceIdentifierAttribute コンストラクタ」の関連用語


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XmlChoiceIdentifierAttribute コンストラクタとは？ わかりやすく解説

XmlChoiceIdentifierAttribute コンストラクタ (String)

XmlChoiceIdentifierAttribute コンストラクタ

関連項目

XmlChoiceIdentifierAttribute コンストラクタ ()

急上昇のことば

「XmlChoiceIdentifierAttribute コンストラクタ」の関連用語

XmlChoiceIdentifierAttribute コンストラクタとは？わかりやすく解説